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In the equilibrium, $A B \rightleftharpoons A+B$, if the equilibrium concentration of $A$ is double, then equilibrium concentration of $B$ will be
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The correct answer is:
half
$A B \rightleftharpoons A+B$
or $K=\frac{[A][B]}{[A B]}$
if concentration of $A$ is doubled, the equilibrium concentration of $B$ becomes half to maintain $K$ constant.
or $K=\frac{[A][B]}{[A B]}$
if concentration of $A$ is doubled, the equilibrium concentration of $B$ becomes half to maintain $K$ constant.
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