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Question: Answered & Verified by Expert
In the expansion of $(1+x)^{50}$, the sum of the coefficients of $\begin{array}{ll}\text { odd powers of } \mathrm{x} \text { is } & \end{array}$
MathematicsBinomial TheoremNDANDA 2017 (Phase 2)
Options:
  • A $2^{26}$
  • B $2^{49}$
  • C $2^{50}$
  • D $2^{51}$
Solution:
1604 Upvotes Verified Answer
The correct answer is: $2^{49}$
Sum of odd terms of expansion $(\mathrm{a}+\mathrm{b})^{\mathrm{n}}$ is $\frac{1}{2} \cdot 2^{\mathrm{n}}$.
$\therefore$ Sum of odd terms of expansion $(1+\mathrm{x})^{50}$ is $\frac{1}{2} \cdot 2^{50}$
$=2^{-1} .2^{50}=2^{49}$

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