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In the extraction of copper from its sulphide ore, the metal is finally obtained by the reduction of cuprous oxide with
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copper (I) sulphide $\left(\mathrm{Cu}_2 \mathrm{~S}\right)$
In the extraction of copper from its sulphide ore, when ore is subjected to roasting, some of it is oxidised to $\mathrm{Cu}_2 \mathrm{O}$ which reacts with the remaining $\mathrm{Cu}_2 \mathrm{~S}$ (sulphide ore) to give copper metal.
$\mathrm{Cu}_2 \mathrm{~S}+2 \mathrm{Cu}_2 \mathrm{O} \longrightarrow 6 \mathrm{Cu}+\mathrm{SO}_2 \uparrow$
In this process $\mathrm{Cu}_2 \mathrm{~S}$ behaves as reducing agent.
$\mathrm{Cu}_2 \mathrm{~S}+2 \mathrm{Cu}_2 \mathrm{O} \longrightarrow 6 \mathrm{Cu}+\mathrm{SO}_2 \uparrow$
In this process $\mathrm{Cu}_2 \mathrm{~S}$ behaves as reducing agent.
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