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In the extraction of copper from its sulphide ore, the metal is formed by the reduction of $\mathrm{Cu}_2 \mathrm{O}$ with
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The correct answer is:
$\mathrm{Cu}_2 \mathrm{~S}$
$\mathrm{Cu}_2 \mathrm{~S}$
In the extraction of copper from its sulphide ore, the metal is formed according to the reaction given :
$$
\mathrm{Cu}_2 \mathrm{O}+\frac{1}{2} \mathrm{Cu}_2 \mathrm{~S} \longrightarrow 3 \mathrm{Cu}+\frac{1}{2} \mathrm{SO}_2
$$
$$
\mathrm{Cu}_2 \mathrm{O}+\frac{1}{2} \mathrm{Cu}_2 \mathrm{~S} \longrightarrow 3 \mathrm{Cu}+\frac{1}{2} \mathrm{SO}_2
$$
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