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In the extraction of copper from sulphide ore the metal is formed by reduction of $\mathrm{Cu}_2 \mathrm{O}$ with
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Verified Answer
The correct answer is:
$\mathrm{FeS}$
Iron has greater affinity for oxygen than copper.
$$
\begin{gathered}
\mathrm{Cu}_2 \mathrm{O}+\mathrm{FeS} \rightarrow \mathrm{FeO}+\mathrm{Cu}_2 \mathrm{~S} \\
\mathrm{FeO}+\mathrm{SiO}_2 \rightarrow \mathrm{FeSiO}_3 \\
(\mathrm{slag})
\end{gathered}
$$
$$
\begin{aligned}
& 2 \mathrm{Cu}_2 \mathrm{~S}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Cu}_2 \mathrm{O}+2 \mathrm{SO}_2 \\
& 2 \mathrm{Cu}_2 \mathrm{O}+\mathrm{Cu}_2 \mathrm{~S} \underset{\text { auto }}{\text { reduction }} 6 \mathrm{Cu}+\mathrm{SO}_2 .
\end{aligned}
$$
$$
\begin{gathered}
\mathrm{Cu}_2 \mathrm{O}+\mathrm{FeS} \rightarrow \mathrm{FeO}+\mathrm{Cu}_2 \mathrm{~S} \\
\mathrm{FeO}+\mathrm{SiO}_2 \rightarrow \mathrm{FeSiO}_3 \\
(\mathrm{slag})
\end{gathered}
$$
$$
\begin{aligned}
& 2 \mathrm{Cu}_2 \mathrm{~S}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Cu}_2 \mathrm{O}+2 \mathrm{SO}_2 \\
& 2 \mathrm{Cu}_2 \mathrm{O}+\mathrm{Cu}_2 \mathrm{~S} \underset{\text { auto }}{\text { reduction }} 6 \mathrm{Cu}+\mathrm{SO}_2 .
\end{aligned}
$$
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