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In the figure, a proton moves a distance \(d\) in a uniform electric field \(\vec{E}\) as shown in the figure. Does the electric field do a positive or negative work on the proton? Does the electric potential energy of the proton increase or decrease?

Here, distance increases so, potential energy increases.
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Here, distance increases so, potential energy increases.
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Verified Answer
The correct answer is:
Negative, increase
Force \(=\mathrm{eE}\)
Workdone \(=\) force \(\times\) distance
Force and distance are in opposite direction, so work is negative.
\(\mathrm{W}=-\mathrm{e} \mathrm{E} \times \mathrm{d}\)
Here, distance increases so, potential energy increases.
Workdone \(=\) force \(\times\) distance
Force and distance are in opposite direction, so work is negative.
\(\mathrm{W}=-\mathrm{e} \mathrm{E} \times \mathrm{d}\)
Here, distance increases so, potential energy increases.
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