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Question: Answered & Verified by Expert
In the figure, mA=2 kg and mB=4 kg . For what minimum value of F,A starts slipping over B g=10m s-2 ?
 
PhysicsLaws of MotionNEET
Options:
  • A 24 N
  • B 36 N
  • C 12 N
  • D 20 N
Solution:
1471 Upvotes Verified Answer
The correct answer is: 36 N
Maximum frictional force between A and B could be

f1=μ1mAg=0.2210 N

f1=4 N

Acceleration when frictional force is maximum,

a=f1mA

a=42=2m/s2

Fictional force between ground and B

f2=μ2mA+mBg

f2=0.42+410

f2=24 N



Therefore for the entire system,

F-f2=mA+mBa

F-24=2+42

F=36 N

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