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Question: Answered & Verified by Expert
In the figure, mA=2 kg and mB=4 kg. For what minimum value of force FA starts slipping over B g=10 m s-2

PhysicsLaws of MotionNEET
Options:
  • A 24 N
  • B 36 N
  • C 12 N
  • D 20 N
Solution:
2532 Upvotes Verified Answer
The correct answer is: 36 N


For A, mAa=fL1

mAa=μ1mAg

a=μ1g

For B,

F-fL1+fL2=mBa

F=μ1mAg+μ2mA+mBg+mBμ1g

F=μ1+μ2mA+mBg

F=0.2+0.42+410

F=36 N

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