In the figure shown, acceleration with which the mass m falls down when released is (consider the string to be massless, g -acceleration due to gravity)

Question

In the figure shown, acceleration with which the mass m falls down when released is (consider the string to be massless, g -acceleration due to gravity), 3 2 g ​, 2 g ​, 6 5 g ​, g

MARKS App · Accepted Answer

Let tension in string is T and tension T is rotating the hollow cylinder. Torque produced in hollow cylinder, $ τ = I α M o m e n t o f in er i t a o f cy l in d er , I=M R^2 w h ere , M= ma sso f cy l in d er an d R= r a d i u so f cy l in d er . im g src = " h ttp s : // c d n − q u es t i o n − p oo l . g e t ma r k s . a pp / p y q / a p e ​ am ce t / t h oz Nww n g J 2 Vm w H F 7 v T v NXt 3 O o bV N U b E i S J lZTw x f F g . or i g ina l . f u ll s i ze . p n g " > b r > A n gu l a r a cce l er a t i o n , \alpha=\frac{a}{R} , w h ere a= a cce l er a t i o n . im g src = " h ttp s : // c d n − q u es t i o n − p oo l . g e t ma r k s . a pp / p y q / a p e ​ am ce t / sc − 78 x Cl 0 k w − b zz 8 W 095 d b c l n I h f Z 13 l 1 vgg MFS x M c Q . or i g ina l . f u ll s i ze . p n g " > b r > Eq u a t in g Eq s . ( i ) an d ( ii ) , w e g e t T R=M R a ⇒ T = M a N o w , \quad M g-T=M a ⇒ a = ​ M g − M a = M a ⇒ 2 M a = M g g /2 ​ $

Search any question & find its solution

Looking for more such questions to practice?