Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In the figure shown, RB=500  RC=8 VBB=10.6 V and VCC=20 V. The current amplification factor β=100 and VBE=0.6 V. Mark the incorrect statement.

PhysicsSemiconductorsJEE Main
Options:
  • A IB=20 μA
  • B VCB=3.4 V
  • C VCE=2.8 V
  • D the transistor is in active region
Solution:
1429 Upvotes Verified Answer
The correct answer is: VCE=2.8 V

VBB  IBRB= VBE

10.6-5×105×IB=0.6

IB=20 μA

IC=100 IB=2000 μA

VCE= VCC ICRC=20-0.002×8000=4 V

VCB=20-0.002×8000-0.6=3.4 V

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.