In the figure, the reverse breakdown voltage of a Zener diode is 5. 6 V , then the current I z through the diode is

Question

In the figure, the reverse breakdown voltage of a Zener diode is 5. 6 V , then the current I z through the diode is, 17 mA, 15 mA, 10 mA, 7 mA

MARKS App · Accepted Answer

For zener break down potential difference across 800 Ω resistor will be 5 . 6 V V z = 5 . 6 V i 2 = V 2 800 = 5 . 6 800 = 7 mA ΔV across 200 Ω = 9 - 5 . 6 = 3 . 4 V i 1 = 3 . 4 200 = 17 mA i 1 = i 2 + i z i z = 17 mA - 7 mA = 10 mA

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