In the first order reaction, the concentration of the reactants is reduced to $ 25 \% $ in one hour. The half-life period of the reaction is

Question

In the first order reaction, the concentration of the reactants is reduced to $ 25 \% $ in one hour. The half-life period of the reaction is, $ 2 \mathrm{~h} $, $ 4 \mathrm{~h} $, $ 1 / 2 \mathrm{~h} $, $ 1 / 4 \mathrm{~h} $

MARKS App · Accepted Answer

For first order reaction, k = 2 .303 t 1 / 2 log a a - a 2 = 2 .303 t log a ( a - x ) 2 .303 t 1 / 2 log ⁡ 2 = 2 .303 1 log a a / 4 2 .303 × 0 .3010 t 1 / 2 = 2 .303 × log ⁡ 4 t 1 / 2 = 0 .3010 log ⁡ 4 = 0 .3010 0 .6020 = 1 2 h

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