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In the following circuit, the $1 \Omega$ resistor dissipates power $P$. If the resistor is replaced by $9 \Omega$, the power dissipated in it is
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$\mathrm{P}$
$10=4 \mathrm{i}$
$\mathrm{i}=\frac{5}{2}$
$\mathrm{P}_{\mathrm{i}}=\mathrm{i}^{2} \mathrm{R}=\left(\frac{5}{2}\right)^{2} \times 1=\frac{25}{4}$
$\mathrm{P}_{\mathrm{f}}=\left(\frac{10}{12}\right)^{2} \times 9=\frac{100}{12 \times 12} \times 9$
$\mathrm{P}_{\mathrm{f}}=\mathbf{P}_{\mathrm{i}}$
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