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In the following circuit, the output $\mathrm{Y}$ for all possible inputs $\mathrm{A}$ and $\mathrm{B}$ is expressed by the truth table.
Options:
- A
- B
- C
- D
Solution:
1945 Upvotes
Verified Answer
The correct answer is:
\(Y^{\prime}=\overline{A+B} . \quad Y=\overline{\overline{A+B}}=A+B\)
Truth table of the given circuit is given by
\(\begin{array}{|c|c|c|c|}
\hline A & B & Y^{\prime} & Y \\
\hline 0 & 0 & 1 & 0 \\
\hline 0 & 1 & 0 & 1 \\
\hline 1 & 0 & 0 & 1 \\
\hline 1 & 1 & 0 & 1 \\
\hline
\end{array}\)
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