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In the following electrical network, the value of $\mathrm{I}$ is
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3.4 A
$\begin{aligned} & \mathrm{I}_4=\mathrm{I}_1+\mathrm{I}_2+\mathrm{I}_3=1+2+3=6 \mathrm{~A} \\ & \mathrm{I}_6=\mathrm{I}_4-\mathrm{I}_5=6-1.2=4.8 \mathrm{~A} \\ & \mathrm{I}_8=\mathrm{I}_6+\mathrm{I}_7=4.8+0.8=5.6 \mathrm{~A} \\ & \mathrm{I}_{10}=\mathrm{I}_8-\mathrm{I}_9=5.6-0.5=5.1 \mathrm{~A} \\ & \mathrm{I}=\mathrm{I}_{10}-\mathrm{I}_{11}=5.1-1.7=3.4 \mathrm{~A}\end{aligned}$
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