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In the following electrical network, the value of ' $\mathrm{I}$ ' is
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The correct answer is:
3.4 A
Current is a scaler quantity.
On current accounting:
$\begin{aligned}
& I_{-}\{\text {in }\}=1 \mathrm{~A}+2 \mathrm{~A}+3 \mathrm{~A}+0.8 \mathrm{~A}=6.8 \mathrm{~A} \\
& \mathrm{I}_{\text {out }}=0.5 \mathrm{~A}+1.2 \mathrm{~A}+1.7 \mathrm{~A}=3.4 \mathrm{~A} \\
& \mathrm{I}=\mathrm{I}_{\text {in }}-\mathrm{I}_{\text {out }}=3.4 \mathrm{~A}
\end{aligned}$
On current accounting:
$\begin{aligned}
& I_{-}\{\text {in }\}=1 \mathrm{~A}+2 \mathrm{~A}+3 \mathrm{~A}+0.8 \mathrm{~A}=6.8 \mathrm{~A} \\
& \mathrm{I}_{\text {out }}=0.5 \mathrm{~A}+1.2 \mathrm{~A}+1.7 \mathrm{~A}=3.4 \mathrm{~A} \\
& \mathrm{I}=\mathrm{I}_{\text {in }}-\mathrm{I}_{\text {out }}=3.4 \mathrm{~A}
\end{aligned}$
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