In the following network, the potential at O is

Question

In the following network, the potential at O is, 4 V, 3 V, 6 V, 4.8 V

MARKS App · Accepted Answer

Let the potential at O is V 0 . Application of Kirchhoff's first law at junction O gives 8 - V 0 2 = V 0 - 4 4 + V 0 - 2 2 = V 0 - 4 + 2 V 0 - 4 4 4 8 - V 0 2 = V 0 - 4 + 2 V 0 - 4 16 - 2 V 0 = 3 V 0 - 8 16 + 8 = 5 V 0 V 0 = 24 5 = 4 .8 V

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