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Question: Answered & Verified by Expert
In the following nuclear reaction $x$ stands for $n \rightarrow p+e^{-}+x$
PhysicsNuclear PhysicsAP EAMCETAP EAMCET 2015
Options:
  • A $\alpha$-particle
  • B positron
  • C nutrino
  • D antinutrino
Solution:
1283 Upvotes Verified Answer
The correct answer is: antinutrino
Here $\frac{n}{p} \downarrow \downarrow$.
So it is $\beta^{-}$decay. So, $x$ stands for antinutrino.

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