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In the following reaction, $A$ and $B$ respectively are
$A \stackrel{\mathrm{HBr}}{\longrightarrow} \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br} \stackrel{B}{\longrightarrow} A$
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$A \stackrel{\mathrm{HBr}}{\longrightarrow} \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br} \stackrel{B}{\longrightarrow} A$
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Verified Answer
The correct answer is:
$\mathrm{C}_2 \mathrm{H}_4$ and alcoholic $\mathrm{KOH} / \Delta$
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