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In the following reaction $\mathrm{a}, \mathrm{b}, \mathrm{p}, \mathrm{q}, \mathrm{r}$ and $\mathrm{s}$ are $\mathrm{a} \mathrm{XeF}+\mathrm{b} \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{p} \mathrm{Xe}+\mathrm{qXeO}_3+\mathrm{rHF}+\mathrm{s} \mathrm{O}_2$
$\begin{array}{llllll}\mathbf{a} & \mathbf{b} & \mathbf{p} & \mathbf{q} & \mathbf{r} & \mathbf{s}\end{array}$
Options:
$\begin{array}{llllll}\mathbf{a} & \mathbf{b} & \mathbf{p} & \mathbf{q} & \mathbf{r} & \mathbf{s}\end{array}$
Solution:
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Verified Answer
The correct answer is:
6 12 4 2 24 3
$6 \mathrm{XeF}_4+12 \mathrm{H}_2 \mathrm{O} \longrightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_3+24 \mathrm{HF}+3 \mathrm{O}_2$
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