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Question:
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In the following reaction,
$$
\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Br} \frac{\text { (i) } \mathrm{Mg}, \text { Ether }}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}} \mathrm{X}
$$
the product ' $\mathrm{X}^{\prime}$ is
Options:
$$
\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Br} \frac{\text { (i) } \mathrm{Mg}, \text { Ether }}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}} \mathrm{X}
$$
the product ' $\mathrm{X}^{\prime}$ is
Solution:
1784 Upvotes
Verified Answer
The correct answer is:
$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}$,
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