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In the following reaction, find the number of products formed which contain carbon atom(s):
Sodium bicarbonate \( \stackrel{\Delta}{\longrightarrow} \) Products
Sodium bicarbonate \( \stackrel{\Delta}{\longrightarrow} \) Products
Solution:
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Verified Answer
The correct answer is:
2
$2 \mathrm{NaHCO}_{3} \stackrel{\Delta}{\longrightarrow} \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2}$
Products containing C-atom: $\mathrm{Na}_{2} \mathrm{CO}_{3}$ and $\mathrm{CO}_{2}$
Products containing C-atom: $\mathrm{Na}_{2} \mathrm{CO}_{3}$ and $\mathrm{CO}_{2}$
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