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Question: Answered & Verified by Expert
In the following reaction :
\(\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \xrightarrow[443 \mathrm{~K}]{\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4} \mathrm{Z} \text {. }\)
Identify \(Z\) :
ChemistryAlcohols Phenols and EthersVITEEEVITEEE 2023
Options:
  • A \(\mathrm{CH}_2=\mathrm{CH}_2\)
  • B \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{O}-\underset{\large | \atop \huge \mathrm{CH}_3}{\mathrm{CH}_2}\)
  • C \(\mathrm{CH}_3-\mathrm{CH}_2-\underset{\large | \atop \huge \mathrm{SO}_4}{\mathrm{C}}\)
  • D \(\left(\mathrm{CH}_3 \mathrm{CH}_2\right)_2-\mathrm{SO}_4\)
Solution:
1257 Upvotes Verified Answer
The correct answer is: \(\mathrm{CH}_2=\mathrm{CH}_2\)
If ethyl alcohol is dehydrolysed by conc. \(\mathrm{H}_2 \mathrm{SO}_4\) at \(443^{\circ} \mathrm{K}\), then ethylene is formed.
\(\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\text { conc. } \mathrm{H}_2 \mathrm{SO}_4} \mathrm{C}_2 \mathrm{H}_4\)

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