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In the following reaction mixtures,
I. $\mathrm{Cu} / \mathrm{CuSO}_4+\mathrm{Ag} / \mathrm{Ag}_2 \mathrm{SO}_4$
II. Zn $/ \mathrm{ZnSO}_4+\mathrm{Cu} / \mathrm{CuSO}_4$
copper respectively undergoes
Options:
I. $\mathrm{Cu} / \mathrm{CuSO}_4+\mathrm{Ag} / \mathrm{Ag}_2 \mathrm{SO}_4$
II. Zn $/ \mathrm{ZnSO}_4+\mathrm{Cu} / \mathrm{CuSO}_4$
copper respectively undergoes
Solution:
1434 Upvotes
Verified Answer
The correct answer is:
oxidation and reduction
So, the reactions can be written as,
(i) $\stackrel{0}{\mathrm{C}} \mathrm{u}+\stackrel{+1}{\mathrm{Ag}} \mathrm{SO}_2 \longrightarrow \stackrel{+2}{\mathrm{Cu}} \mathrm{SO}_4+2 \stackrel{0}{2 \mathrm{Ag}}$
(ii) $\stackrel{0}{\mathrm{Zn}}+\stackrel{+2}{\mathrm{Cu}} \mathrm{SO}_4 \longrightarrow \stackrel{+2}{\mathrm{ZnSO}_4}+\stackrel{0}{\mathrm{C} u}$
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