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In the following reaction order, $B$ is
Options:
- A $\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH}$
- B
- C $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COBr}$
- D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH}$
$\mathrm{P}+\mathrm{Br}_2$ is brominating agent that brominates the $\alpha$-position. The product then undergo dehydrohalogenation in the presence of alcoholic potassium hydroxide.
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