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Question: Answered & Verified by Expert
In the following reaction sequence, $\mathrm{CH}_{3} \mathrm{CHO} \frac{\mathrm{Cl}_{2}}{\mathrm{Ca}(\mathrm{OH})_{2}} \times \frac{\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}}{\mathrm{Alc} . \mathrm{KOH}} Y$
$Y$ is
ChemistryAminesMHT CETMHT CET 2010
Options:
  • A $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NHC}_{6} \mathrm{H}_{5}$
  • B $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHCH}_{3}$
  • C $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NC}$
  • D $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NCO}$
Solution:
1936 Upvotes Verified Answer
The correct answer is: $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NC}$
$\mathrm{CH}_{3} \mathrm{CHO}+\mathrm{Cl}_{2} \longrightarrow \underset{\text { chloral }}{\mathrm{CCl}_{3} \mathrm{CHO}} \stackrel{\mathrm{Ca}(\mathrm{OH})_{2}}{\longrightarrow} \underset{\begin{array}{c}\text { Chloroform } \\ (X)\end{array}}{\mathrm{CHCl}_{3}}$

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