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In the following reaction sequence, the amount of (in g) formed from moles of acetophenone is ____.
(Atomic weights in The yield (%) corresponding to the product in each step is given in the parenthesis)

(Atomic weights in The yield (%) corresponding to the product in each step is given in the parenthesis)
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Verified Answer
The correct answer is:
495
molecular weight of
= 330

Weight of 1 mol of 2, 4, 6 tribromoaniline = 330 gm
∴ Weight of 1.5 mol of 2, 4, 6 tribromoaniline = 330 × 1.5 = 495 gm

Weight of 1 mol of 2, 4, 6 tribromoaniline = 330 gm
∴ Weight of 1.5 mol of 2, 4, 6 tribromoaniline = 330 × 1.5 = 495 gm
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