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In the following reaction, $X$ and $Y$ are respectively
$$
\mathrm{CH}_3 \mathrm{COOH}+\mathrm{NH}_3 \longrightarrow X \stackrel{\Delta}{\longrightarrow} Y+\mathrm{H}_2 \mathrm{O}
$$
Options:
$$
\mathrm{CH}_3 \mathrm{COOH}+\mathrm{NH}_3 \longrightarrow X \stackrel{\Delta}{\longrightarrow} Y+\mathrm{H}_2 \mathrm{O}
$$
Solution:
1292 Upvotes
Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{COONH}_4, \mathrm{CH}_3 \mathrm{CONH}_2$
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