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In the following reaction, $X$ and $Y$ respectively are
$\begin{aligned} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \longrightarrow \stackrel{\mathrm{KMnO}_4 / \mathrm{H}^{+}}{\longrightarrow} & X \\ \stackrel{\mathrm{H}_2}{ } \frac{Y}{\mathrm{SO}_4 / \Delta} & \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5\end{aligned}$
Options:
$\begin{aligned} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \longrightarrow \stackrel{\mathrm{KMnO}_4 / \mathrm{H}^{+}}{\longrightarrow} & X \\ \stackrel{\mathrm{H}_2}{ } \frac{Y}{\mathrm{SO}_4 / \Delta} & \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5\end{aligned}$
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{COOH}, \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$
$\begin{aligned} & \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+[\mathrm{O}] \stackrel{\mathrm{KMnO}_4 / \mathrm{H}^{+}}{\longrightarrow} \mathrm{CH}_3 \mathrm{CHO}+\mathrm{H}_2 \mathrm{O} \\ & \mathrm{CH}_3 \mathrm{CHO}+[\mathrm{O}] \stackrel{\mathrm{KMnO}_4 / \mathrm{H}^{+}}{\longrightarrow} \mathrm{CH}_3 \mathrm{COOH} \\ & (\mathrm{X}) \\ & \mathrm{CH}_3 \mathrm{COOH} \underset{\substack{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}(\mathrm{Y}) \\ \text { (esterification) }}}{\longrightarrow} \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5+\mathrm{H}_2 \mathrm{O}\end{aligned}$
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