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In the following sequence of reactions,
$$
\begin{array}{r}
\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \stackrel{\mathrm{P}+\mathrm{I}_2}{\longrightarrow} \mathrm{A} \underset{\text { ether }}{\stackrel{\mathrm{Mg}}{\longrightarrow}} \mathrm{B} \stackrel{\mathrm{HCHO}}{\longrightarrow} \\
\mathrm{C} \stackrel{\mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{D}
\end{array}
$$
the compound $\mathrm{D}$ is
Options:
$$
\begin{array}{r}
\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \stackrel{\mathrm{P}+\mathrm{I}_2}{\longrightarrow} \mathrm{A} \underset{\text { ether }}{\stackrel{\mathrm{Mg}}{\longrightarrow}} \mathrm{B} \stackrel{\mathrm{HCHO}}{\longrightarrow} \\
\mathrm{C} \stackrel{\mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{D}
\end{array}
$$
the compound $\mathrm{D}$ is
Solution:
1543 Upvotes
Verified Answer
The correct answer is:
$n$-propyl alcohol.
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