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In the following sequence of reactions, the alkene affords the compound ' $B$ ' $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3 \stackrel{\mathrm{O}_3}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{H}_2 \mathrm{O}}{\mathrm{Zn}} \mathrm{B}$.
The compound $\mathrm{B}$ is
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The compound $\mathrm{B}$ is
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The correct answer is:
$\mathrm{CH}_3 \mathrm{CHO}$
$\mathrm{CH}_3 \mathrm{CHO}$
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