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In the following sequence of reactions
The final product \( C \) is
Options:
The final product \( C \) is
Solution:
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Verified Answer
The correct answer is:
Ethyl Alcohal
The reaction involved is,
\( \mathrm{CH}_{3} \mathrm{Br}+\mathrm{KCN} \rightarrow \mathrm{CH}_{3} \mathrm{CN}+\mathrm{KBr} \)
(B)
\( \mathrm{LiAlH}_{4} \)
(B)
(C)
\( \mathrm{CH}_{3} \mathrm{Br}+\mathrm{KCN} \rightarrow \mathrm{CH}_{3} \mathrm{CN}+\mathrm{KBr} \)
(B)
\( \mathrm{LiAlH}_{4} \)
(B)
(C)
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