Search any question & find its solution
Question:
Answered & Verified by Expert
In the following unbalanced reaction, the product formed is
$\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}(a q)+\mathrm{H}_2 \mathrm{O} \longrightarrow$
Options:
$\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}(a q)+\mathrm{H}_2 \mathrm{O} \longrightarrow$
Solution:
2351 Upvotes
Verified Answer
The correct answer is:
$\mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]$
Aluminium oxide reacts with aqueous solution of sodium hydroxide to form sodium hexahydroxyaluminate (III).
$\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]$
$\mathrm{Al}_2 \mathrm{O}_3+\mathrm{NaOH}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Na}_3\left[\mathrm{Al}(\mathrm{OH})_6\right]$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.