In the formation of sodium chloride, what is the half reaction for the loss of electrons by sodium?

Question

In the formation of sodium chloride, what is the half reaction for the loss of electrons by sodium?, 2 Na(s) → 2 Na+(g) + 2e-, Cl 2 (g) + 2e- → 2 Cl-(g), 2 Na(s) + Cl 2 (g) → 2 Na+ Cl-(s), 2 Na(s) + 2e- → 2 Na+(g)

MARKS App · Accepted Answer

The passage provides the half reaction for the loss of electrons by sodium as 2 Na(s) → 2 Na+(g) + 2e-.

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