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In the Freundlich isotherm $\left(\frac{\chi}{m}=k_P{ }^{1 / n}\right)$ plot of $\log \frac{x}{m} v s \log p$, the intercept is (where, $x, m, p$ and $k$ are mass of the gas, mass of adsorbent, pressure and constant which depend on the nature of the adsorbent, respectively)
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Verified Answer
The correct answer is:
$\log k$

For Freundlich adsorption isotherm equation
$$
\frac{x}{m}=k_p^{\frac{1}{n}}
$$
or
$$
\log \frac{x}{m}=\log k+\frac{1}{n} \log p
$$
A plot of $\log \frac{x}{m}$ versus $\log p$ is linear with slope $=\frac{1}{n}$ and intercept $=\log k$.
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