Search any question & find its solution
Question:
Answered & Verified by Expert
In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is $0.01 \mathrm{~s}$. The fundamental frequency is
Options:
Solution:
2919 Upvotes
Verified Answer
The correct answer is:
25
In the fundamental mode,
Frequency, $n=\frac{v}{\lambda}$
$$
\begin{array}{l}
n=\frac{v}{4 l} \\
n=\frac{l}{t \times 4 l} \quad\left[\because v=\frac{l}{t}\right] \\
n=\frac{1}{0.01 \times 4} \\
n=25
\end{array}
$$
Frequency, $n=\frac{v}{\lambda}$
$$
\begin{array}{l}
n=\frac{v}{4 l} \\
n=\frac{l}{t \times 4 l} \quad\left[\because v=\frac{l}{t}\right] \\
n=\frac{1}{0.01 \times 4} \\
n=25
\end{array}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.