In the Gattermann reaction, a diazonium group is replaced by $ \mathrm{X} $ using $ \mathrm{Y} ; \mathrm{X} $ and $ \mathrm{Y} $ are

Question

In the Gattermann reaction, a diazonium group is replaced by $ \mathrm{X} $ using $ \mathrm{Y} ; \mathrm{X} $ and $ \mathrm{Y} $ are, $\mathrm{X} \text{ and } \mathrm{Y} =\mathrm{Cl}^{-} \quad =\mathrm{Cu} / \mathrm{HCl} $, $\mathrm{X} \text{ and } \mathrm{Y} =\mathrm{Cl}^{+} \quad \mathrm{Y}=\mathrm{CuCl}_{2} / \mathrm{HCl} $, $\mathrm{X} \text{ and } \mathrm{Y} =\mathrm{Cl}^{-} \quad \mathrm{Y}=\mathrm{CuCl}_{2} / \mathrm{HCl} $, $\mathrm{X} \text{ and } \mathrm{Y} =\mathrm{Cl}_{2} \mathrm{Y}=\mathrm{Cu}_{2} \mathrm{O} / \mathrm{HCl} $

MARKS App · Accepted Answer

When the benzene diazonium salt reacts with the halogen in the presence of copper powder, then it is known as the Gatterman reaction. ArN 2 + Cl - + HCl → Cu ArCl + N 2 + CuCl So, X - Cl - & Y = Cu / HCl .

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