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In the given circuit, find the energy stored in the coil at steady state.
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Verified Answer
The correct answer is:
0
Given that, a circuit containing 5 resistances with a battery as shown in figure.
Rearranging the circuit, we get a balanced Wheatstone bridge
As $\frac{R_1}{R_2}=\frac{R_3}{R_4}=\frac{2}{5}$
$\therefore$ No current will pass through the inductor coil i.e., $I=0$
Now, energy stored in inductor is
$$
U=\frac{1}{2} L I^2
$$
Hence, $U=0$
Rearranging the circuit, we get a balanced Wheatstone bridge
As $\frac{R_1}{R_2}=\frac{R_3}{R_4}=\frac{2}{5}$
$\therefore$ No current will pass through the inductor coil i.e., $I=0$
Now, energy stored in inductor is
$$
U=\frac{1}{2} L I^2
$$
Hence, $U=0$
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