Search any question & find its solution
Question:
Answered & Verified by Expert
In the given circuit, find voltage across $12 \Omega$ resistance.
Options:
Solution:
2815 Upvotes
Verified Answer
The correct answer is:
48 Volt
If $\mathrm{R}_1$ be the equivalent resistance of parallel resistors $8 \Omega, 8 \Omega$ and $4 \Omega$, then
$\frac{1}{\mathrm{R}_1}=\frac{1}{8}+\frac{1}{8}+\frac{1}{4}=\frac{4}{8} \Rightarrow \mathrm{R}_1=2 \Omega$
$\therefore$ Total resistance of upper branch,
$\mathrm{R}_2=\mathrm{R}_1+4=2+4=6 \Omega$
Now circuit can be redraw of
By current division rule, current through $12 \Omega$ resistor $\mathrm{I}_2=\frac{12 \times 6}{12+6}=12 \times \frac{1}{3}=4 \mathrm{~A}$
$\therefore$ Voltage across $12 \Omega$ resistor
$\mathrm{V}=\mathrm{I}_2 \mathrm{R}=4 \times 12=48 \mathrm{~V}$
$\frac{1}{\mathrm{R}_1}=\frac{1}{8}+\frac{1}{8}+\frac{1}{4}=\frac{4}{8} \Rightarrow \mathrm{R}_1=2 \Omega$
$\therefore$ Total resistance of upper branch,
$\mathrm{R}_2=\mathrm{R}_1+4=2+4=6 \Omega$
Now circuit can be redraw of
By current division rule, current through $12 \Omega$ resistor $\mathrm{I}_2=\frac{12 \times 6}{12+6}=12 \times \frac{1}{3}=4 \mathrm{~A}$
$\therefore$ Voltage across $12 \Omega$ resistor
$\mathrm{V}=\mathrm{I}_2 \mathrm{R}=4 \times 12=48 \mathrm{~V}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.