Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In the given circuit, r.m.s. value of current through the resistor $\mathrm{R}$ is

PhysicsAlternating CurrentMHT CETMHT CET 2023 (12 May Shift 1)
Options:
  • A $2 \mathrm{~A}$
  • B $0.5 \mathrm{~A}$
  • C $20\mathrm{~A}$
  • D $2 \sqrt{2} \mathrm{~A}$
Solution:
1231 Upvotes Verified Answer
The correct answer is: $2 \mathrm{~A}$
$\begin{aligned} \mathrm{Z} & =\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}\right)^2} \\ \mathrm{Z} & =\sqrt{100^2+100^2} \\ \mathrm{Z} & =100 \sqrt{2} \Omega \\ \mathrm{i}_{\mathrm{rms}} & =\frac{\mathrm{V}_{\mathrm{rms}}}{\mathrm{Z}} \\ \therefore \quad \mathrm{i}_{\mathrm{rms}} & =\frac{200 \sqrt{2}}{100 \sqrt{2}} \\ \mathrm{i}_{\mathrm{rms}} & =2 \mathrm{~A}\end{aligned}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.