In the given circuit switch $\mathrm{K}$ is open. The charge on the capacitor is $\mathrm{C}$ in steady-state is ${\mathrm{q}}_1$. Now the key is closed and steady-state charge on $\mathrm{C}$ is ${\mathrm{q}}_2$. The ratio of charges ${\mathrm{q}}_1/{\mathrm{q}}_2$ is -