Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In the given circuit the average power developed is:

PhysicsAlternating CurrentNEET
Options:
  • A 502 watt
  • B 200 watt
  • C 1502 watt
  • D 2002 watt
Solution:
1026 Upvotes Verified Answer
The correct answer is: 200 watt
Impedance of the circuit is given by

Z=R2+XL2=R2+(ωL)2 ,

Z=(50)2+(0.2×250)2

Z=2500+(50)2=502

Average power is given by

P=VrmsIrmscosϕ



P= Vrms2Z2R

P=200225022×50=200 watt

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.