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In the given circuit, the binary inputs at $A$ and $B$ are both 1 in one case and both 0 in the next case. The respective outputs at $Y$ in these two cases will be
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1115 Upvotes
Verified Answer
The correct answer is:
0,0
The output of logic gate circuit
for
$$
\begin{array}{l}
Y=\frac{}{A \cdot B+\bar{A} \bar{B}} \\
A=1
\end{array}
$$
$$
B=1 \Rightarrow Y=0
$$
and for $\quad A=0, B=0$
$\Rightarrow \quad Y=0$
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