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In the given circuit, the current through \( 2 \Omega \) resistor is
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2107 Upvotes
Verified Answer
The correct answer is:
\( 0.4 \mathrm{~A} \)
(A)
\[
\begin{array}{l}
R_{e q}=(1+2) \Omega=3 \Omega \\
I=\frac{V}{R_{e q}}=\frac{1.2}{3}=0.4 \mathrm{~A}
\end{array}
\]
\[
\begin{array}{l}
R_{e q}=(1+2) \Omega=3 \Omega \\
I=\frac{V}{R_{e q}}=\frac{1.2}{3}=0.4 \mathrm{~A}
\end{array}
\]
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