Let ${\text{I}}_1$ is current flowing through first loop.

$\therefore {\text{I}}_1=\frac{2}{3+2}=\frac{2}{5}\text{A}$



and ${\text{I}}_2$ is current flowing through the second loop.

$\therefore {\text{I}}_2=\frac{4}{3+5}=\frac{1}{2}\text{A}$

Let ${\text{V}}_{\text{A}}$ is potential of point $\text{A}$ and ${\text{V}}_{\text{B}}$ is potential of point $\text{B}.$

Now, we apply Kirchhoff's law between points $\text{A}$ and $\text{B}$.

${\text{V}}_{\text{A}}+3{\text{I}}_1+4+3{\text{I}}_2=V_{\text{B}}$

${\text{V}}_{\text{B}}-{\text{V}}_{\text{A}}=1.2+4+1.5$

$=6.7\text{V}$

Hence, (1) is the correct option.