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In the given circuit the reading of voltmeter $V_1$ and $V_2$ are $300 \mathrm{~V}$ each. The reading to the voltmeter $\mathrm{V}_3$ and ammeter $A$ are respectively
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$220 \mathrm{~V}, 2.2 \mathrm{~A}$
For series $L C R$ circuit
voltage $\mathrm{V}=\sqrt{\mathrm{V}_{\mathrm{R}}^2+\left(\mathrm{V}_{\mathrm{L}}-\mathrm{V}_{\mathrm{C}}\right)^2}$
Since, $V_L=V_C$ hence $V=V_R=220 \mathrm{~V}$
also, current $\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{220}{100}=2.2 \mathrm{~A}$
voltage $\mathrm{V}=\sqrt{\mathrm{V}_{\mathrm{R}}^2+\left(\mathrm{V}_{\mathrm{L}}-\mathrm{V}_{\mathrm{C}}\right)^2}$
Since, $V_L=V_C$ hence $V=V_R=220 \mathrm{~V}$
also, current $\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{220}{100}=2.2 \mathrm{~A}$
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