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In the given circuit the reading of voltmeter $V_{1}$ and $V_{2}$ are 300 volt each. The reading of the voltmeter $V_{3}$ and ammeter $A$ are respectively
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$220 V$ and $2.2 A$
As $V_{L}=V_{C}=300 V$, resonance will take place $\therefore V_{R}=220 V ; I=\frac{220}{100}=2.2 \mathrm{~A}$
reading of $V_{3}=220 \mathrm{~V}$ and reading of $A=2.2 \mathrm{~A}$
reading of $V_{3}=220 \mathrm{~V}$ and reading of $A=2.2 \mathrm{~A}$
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