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In the given circuit, the terminal potential difference of the cell is :
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$2 \mathrm{~V}$
$\begin{aligned} \mathrm{i} & =\frac{3}{1+2}=1 \mathrm{~A} \\ \mathrm{v} & =\mathrm{E}-\mathrm{ir} \\ & =3-1 \times 1=2 \mathrm{~V}\end{aligned}$
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