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In the given figure an ammeter A consists of a $240 \Omega$ coil connected in parallel to a $10 \Omega$ shunt. The reading of the ammeter is $\qquad$ $\mathrm{mA}$
Solution:
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Verified Answer
The correct answer is:
160
Req
$\begin{aligned}
& =140.4+\frac{240 \times 10}{240+10} \\
& \text { Req }=140.4+\frac{2400}{250} \\
& \text { Req. }=150 \Omega
\end{aligned}$
$\begin{aligned} \therefore \text { Current in ammeter } & =\frac{24}{150} \\ & =160 \mathrm{~mA}\end{aligned}$
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