Search any question & find its solution
Question:
Answered & Verified by Expert
In the given figure, the equivalent capacitance between points $A$ and $B$ is
Options:
Solution:
2685 Upvotes
Verified Answer
The correct answer is:
$1.5 \mathrm{C}$
Both parts have capacitors in parallel. The equivalent capacitor for each part is $\mathrm{C}_{\mathrm{eq}}=\mathrm{C}+\mathrm{C}+\mathrm{C}=3 \mathrm{C}$
There are two $3 \mathrm{C}$ capacitances in series
$\therefore \quad \frac{1}{\mathrm{C}_{\mathrm{AB}}}=\frac{1}{3 \mathrm{C}}+\frac{1}{3 \mathrm{C}}$
$\frac{1}{C_{A B}}=\frac{2}{3 C}$
$\therefore \quad \mathrm{C}_{\mathrm{AB}}=1.5 \mathrm{C}$
There are two $3 \mathrm{C}$ capacitances in series
$\therefore \quad \frac{1}{\mathrm{C}_{\mathrm{AB}}}=\frac{1}{3 \mathrm{C}}+\frac{1}{3 \mathrm{C}}$
$\frac{1}{C_{A B}}=\frac{2}{3 C}$
$\therefore \quad \mathrm{C}_{\mathrm{AB}}=1.5 \mathrm{C}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.